Question

answer this :-


thanks :)

Answer 1

Hi,

Let the reservation charge for one ticket = Rs x

one full ticket charge = Rs y

fare of one full ticket with reservation

x + y = 216 ----( 1 )



fare one half ticket with reservation

=x + y/2

According to the problem given,

one full one half ticket charge's

+ reservation charges = 327

x + y + x + y /2 = 327

4x + 3y = 654 ----( 2 )

multiply ( 1 ) with 4 and subtract from ( 2 )

-y = - 210

y = 210

put y in ( 1 ) we get,

x = 6

Therefore,

basic fare of the full ticket = y = Rs 210

reservation charges = Rs 6

I hope this helps you.

:)