answer this with all steps please
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(3/x+y)+(2/x-y)=3. (2/x+y)+(3/x-y)=11/3
3(1/x+y)+2(1/x-y)=3. 2(1/x+y)+3(1/x-y)=11/3
let 1/x+y be a and 1/x-y be b
→3a+2b=3. →2a+3b=11/3
this is first equation and this is second equation
First equation
3a+2b=3
3a=3-2b
a=3-2b/3
substitute a value in equation 2
3(1/x+y)+2(1/x-y)=3. 2(1/x+y)+3(1/x-y)=11/3
let 1/x+y be a and 1/x-y be b
→3a+2b=3. →2a+3b=11/3
this is first equation and this is second equation
First equation
3a+2b=3
3a=3-2b
a=3-2b/3
substitute a value in equation 2
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