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(x-2) is a factor of (x3-8)
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Let p(x) = x3 – 8
x – 2 will be a factor of p(x) if p(2) = 0
Now, p(2) = 23 – 8 = 8 – 8 = 0
Thus, x – 2 will be a factor of x3 – 8
Let p(x) = x3 – 8
x – 2 will be a factor of p(x) if p(2) = 0
Now, p(2) = 23 – 8 = 8 – 8 = 0
Thus, x – 2 will be a factor of x3 – 8
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