Question

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Answer 1

Given : PL ⊥ OA , PM ⊥ OB and PL = PM

To prove : ∆ PLO ≅ ∆ PMO

Solution :

Consider ∆ OLP & ∆ OMP

=> ∠ OLP = OMP ( Each 90° )

=> OP = OP ( Common in both triangles )

=> PL = PM ( Given )

Therefore, ∆ PLO ≅ ∆ PMO by RHS ( Right angle, Hypotenuse, Side )

Hence proved.

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