answer thisquestion. ................ A ladder 10m long reaches a window 8m above the ground. Find the distance of the foot of the ladder from base of. the wall.
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Given
Length of the ladder = 10m
Height of window = 8m
Let the distance of the foot of the ladder from the base of the wall be = x
since the wall is perpendicular to the ground, it forms a right angled triangle
using Pythagoras theorem
(Hypotenuse)² = (height)² × (base)²
10² = 8² + x²
100 = 64 + x²
x² = 100 - 64
x² = 36
x = 6m
The distance of the foot of the ladder from the base of the wall = 6m
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