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Answered by
6
Hi there !!
Here's your answer
Given,
to factorise
(x² - y²)z + (y² - z²)x
Multiplying the terms with their corresponding brackets,
we have,
x²z - y²z + xy² - xz²
Regrouping the terms , we have,
x²z - xz² - y²z + xy²
Taking out common factors,
we have,
xz( x - z ) + y²( -z + x)
= xz(x - z) + y² (x - z)
Taking (x - z) as common factor,
we have,
(xz + y²)(x - z) [ Answer ]
Here's your answer
Given,
to factorise
(x² - y²)z + (y² - z²)x
Multiplying the terms with their corresponding brackets,
we have,
x²z - y²z + xy² - xz²
Regrouping the terms , we have,
x²z - xz² - y²z + xy²
Taking out common factors,
we have,
xz( x - z ) + y²( -z + x)
= xz(x - z) + y² (x - z)
Taking (x - z) as common factor,
we have,
(xz + y²)(x - z) [ Answer ]
Anonymous:
:-)
Answered by
12
Hey there!
To factorise :
( x² - y² ) z + ( y²-z²)x
= x²z - y²z + y²x -z²x
= x²z - z²x + y² ( x - z)
= xz ( x - z) + y² ( x - z)
= ( x - z) ( xz + y² )
Hope helped !
To factorise :
( x² - y² ) z + ( y²-z²)x
= x²z - y²z + y²x -z²x
= x²z - z²x + y² ( x - z)
= xz ( x - z) + y² ( x - z)
= ( x - z) ( xz + y² )
Hope helped !
won't it be (x - z)(x² + yz ) and not (x - z)(x² + xy) ?
Do you think, I did any mistake ?
got ya, thanks
:-)
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