Question

Answer. (U)
The mass of 2240 ml of CO2 at NTP will be
(a) 4.0 g
(c) 8.8 g
no vino
(b) 4.4g
(d) 8.0 g​

Answer 1

Answer:

I think option (B) is correct

Answer 2

The mass of 2240 ml of CO2 at NTP will be 4.4g (option-b).

Given: Volume of CO₂ at NTP, V = 2240 ml

To Find: Mass of CO₂, m.

Solution:

To calculate m, the formula used:

• Number of moles, n = mass(m) / Molar mass(M)
• n = m/M                                        ⇒ 1

At NTP, 1 mole of gas occupies 22.4L of volume, so at 2240ml, Number of moles in 2240ml of gas is 2240 / 22.4

Converting mL into L :

1L = 1000ml

2240 ml = 1 x 2240 / 1000

              = 2240/1000

              = 2.24L

∴ Number of moles = 2.24/22.4

   Number of moles = 0.1 mol             ⇒   2

Equating equations 1 and 2 :

m/M = 1                                                 ⇒    3

The molar mass of CO₂, M = 12 + 2x16

                                             = 12 + 32

                                        M = 44 g/mol

Putting the value of M in equation 3 :

m / 44 = 0.1

m = 0.1 x 44

   = 4.4

m = 4.4g

Hence, the mass of 2240ml of CO₂ at NTP is 4.4g.