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Let the hypotenuse be x. Using the pythagorean theorem:
(x/2)^2 + 3 = x^2
x^2+12 = 4x^2
12 = 3x^2
x^2 = 4
x = 2
so the side length is 2, and the perimeter is 6
(x/2)^2 + 3 = x^2
x^2+12 = 4x^2
12 = 3x^2
x^2 = 4
x = 2
so the side length is 2, and the perimeter is 6
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