Question

answer will mark as brainliest​

Answer 1

Answer:

$\frac{6 {x}^{3} + 8x {}^{2} }{2x}$

$= \frac{6x {}^{3} }{2x} + \frac{8x {}^{2} }{2x}$

$= 3x {}^{2} + 4x$

2)

$3a + 9 = 0$

$3( - 3) + 9 = 0$

$- 9 + 9 = 0$

$0 = 0$

-3 is the answer

Answer 2

FINAL ANSWER:

b) $3x^{2}+4x$

b) -3

GIVEN:

1) (6x³+8x²)/2x

2) 3a+9=0

TO FIND:

1) it's quotient

2) a=?

SOLUTION:

1)    $\frac{6x^{3}+8x^{2}}{2x} \\=3x^{2}+4x$

2) 3a+9=0

    3(-3)+9=0

     -9+9=0

     0=0

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