Answer with explanation..
1.Find the greatest 4-digit number exactly divisible by 20,25 and 56
2.Find the least number which when divided by 16,24 and 32 leaves 5 as remainder.
Answer it in full explaination ie. statement
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1. the answer is 9800
Step-by-step explanation:
firstly we will take the L. C. M of 20,25 and 56..
2 | 20 25 56
2 | 20 25 562 | 10 25 28
2 | 20 25 562 | 10 25 28
2 | 20 25 562 | 10 25 28 5 | 05 25 14
2 | 20 25 562 | 10 25 28 5 | 05 25 14 | 01 05 14
2 | 20 25 562 | 10 25 28 5 | 05 25 14 | 01 05 14then we will multiply 2×2×5×5×14=1400
2 | 20 25 562 | 10 25 28 5 | 05 25 14 | 01 05 14then we will multiply 2×2×5×5×14=1400Then 9900÷1400= we get 199 as remainder and then we will subtract it from 9900 and we get 9800 and this number is divided by 20 , 25 and 56
2 | 20 25 562 | 10 25 28 5 | 05 25 14 | 01 05 14then we will multiply 2×2×5×5×14=1400Then 9900÷1400= we get 199 as remainder and then we will subtract it from 9900 and we get 9800 and this number is divided by 20 , 25 and 56I hope it is helful.....
2 | 20 25 562 | 10 25 28 5 | 05 25 14 | 01 05 14then we will multiply 2×2×5×5×14=1400Then 9900÷1400= we get 199 as remainder and then we will subtract it from 9900 and we get 9800 and this number is divided by 20 , 25 and 56I hope it is helful.....Plz mark me as brainliest✨✨
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