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C3H8 + 5O2 -------) 3CO2 + 4H2O
:.For combustion of 1 mol C3H8.... 5 mol O2 is required.
So at same temp. and pressure conditions
we know that from Charles law
V is directly proportional to n
here V is Volume and n is no. of moles
So we concluded that ....
Volume of Oxygen is 5litres (a option).
:)
:.For combustion of 1 mol C3H8.... 5 mol O2 is required.
So at same temp. and pressure conditions
we know that from Charles law
V is directly proportional to n
here V is Volume and n is no. of moles
So we concluded that ....
Volume of Oxygen is 5litres (a option).
:)
Aman1215:
tysm
U r welcome ... :)
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The three most common methods are basin irrigation, border irrigation and furrow irrigation. Water is typically introduced at the highest point or along the edge of a field, which allows covering the field by overland flow.
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