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8 cos^3(π/9) - 6 cos(π/9)
we know that
4cos^3A = 3 cosA + cos3A
2*(4cos^3(π/9) - 6cos(π/9)
= 2*(3cos(π/9) + 2*cos(3*π/9) - 6 cos(π/9)
= 6 cos(π/9) + 2* cos(π/3) - 6 cos(π/9)
= 2*cos(π/3)
= 2*1/2
= 1
proved
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