Question

answer with full explanation

From a circular card sheet of radius 28cm, two circles of radius 7 cm and a rectangle of length 3 cm and breadth 2 centimeter are removed. Find the area of the remaining sheet.

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Answer 1

Answer:

≡QUESTION≡

From a circular card sheet of radius 28 cm, two circles of radii 7 cm and a rectangle of length 3 cm and breadth 2 cm are removed. Find the area of the remaining sheet.

                                                                                     

║⊕ANSWER⊕║

Total area of sheet = πr²

                                 =22/7 * 28 * 28

                                 =2464 cm²

Area of 2 circles = 2πr²

                             =2 * 22/7 * 7 * 7

                              =308 cm²

Area of rectangle = 3 * 2

                               = 6 cm ²

Area of remaining sheet = area of total sheet - [area of 2 circles+area of rect.]

                                          = 2464 - (308+6)

                                           =2150 cm²

                                                                                         

Answer 2

$\huge\underline\bold\red{Given}$

From a circular card sheet of radius 28cm, two circles of radius 7 cm and a rectangle of length 3 cm and breadth 2 centimeter are removed.

$\huge\underline\bold\orange{To\:Find}$

The area of the remaining sheet.

$\huge\underline\bold\pink{Answer}$

${\boxed{\green{\sf{(formula)\:circle=pie\:r\:square}}}}$

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Radius of big circle sheet (R)= 28cm

Area of big circle sheet (A)= πr²

Area = $\frac{22}{7}$×28×28

Area = $\cancel\frac{22}{7}×28×\cancel{28}$

Area➛22×28×4

Area➛88×4

Area➛2464 cm²

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Radius of small circle (r)= 7 cm

Diameter of small circle (a¹)= πr²

➛$\frac{22}{7}$×7×7

➛22×7

➛154cm²

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Length of rectangle (L)= 3 cm

Breadth of rectangle (B)= 2 cm

Area of rectangle (a²)= L×B

⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀ =3×2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀(a²)= 6 cm²

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A.T.Q

Area of remaining sheet = A-(2×a)=a²

➛2464(2×154)-6

➛2464-308-6

➛2464-314

➛2150 cm²

$\huge\underline\bold\purple{ThankYou}$