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Answer:
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Explanation:
Initial velocity of motorboat, u = 0
Acceleration of motorboat, a=3.0ms-2
Time under consideration, or time taken t = 8.0s
Formula
We know the equation of motion
Distance, s=ut + (1/2)at2 —————-(i)
Substituting the given and known values in equation (i) we get,
s= o (8) + 1/2 (3) (8)2
= 1/2 (3) (64) { 82 = 8 X 8=64}
= 3 (32)
= 96
Therefore, The distance travel by motorboat = 96 m
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Question :
A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m/s² for 8.0 s. How far does the boat travels during this time?
Given :
- Initial velocity, u = 0 m/s (starting from rest)
- Acceleration, a = 3.0 m/s² or 3.0 m/s²
- Time taken, t = 8.0 seconds or 8 seconds
To find :
- Distance travelled by the boat
According to the question,
➞ s = ut + ½ at²
Where,
- a = Acceleration
- s = Distance
- t = Time taken
- u = Initial velocity
➞ Substituting the values,
➞ s = 0 × 8 + ½ × 3 × 8 × 8
➞ s = 0 + 3 × 8 × 4
➞ s = 0 + 96
➞ s = 96
- So, the distance travelled by the boat is 96 meters.
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More formula's :
Newton's first equation of motion :
- v = u + at
Newton's second equation of motion :
- s = ut + ½ at²
Newton's third equation of motion :
- v² = u² + 2as