Question

answer with working
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Answer 1

Answer:

Given, x, 2x+2,3x+3 is in G.P

Hence, by b^2=ac

(2x+2)^2=x(3x+3)

4x^2+4+8x=3x^2+3x

x^2+5x+4=0

x= -1 and x= -4

Now the numbers are, -1, 0, 0(not possible)

or -4, -6, -9

Now, 5x, 10x+10, 15x+15 = -20, -30, -45

these numbers are neither in GP, Nor in AP

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