Math, asked by durva699, 1 year ago

answer with written proof

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Answered by Avengers00
3
\frac{Cos\: 70}{Sin\: 20} + \frac{Cos\: 59}{Sin\: 31}- 8Sin^{2}\: 30

Cos\: \theta = Sin\: (90-\theta)

&
Sin\: 30 = \frac{1}{2}

=> \frac{Sin\: (90-20)}{Sin\: 20} + \frac{Sin\: (90-31)}{Sin\: 31}- 8(\frac{1}{2})^{2}

=> \frac{Sin\: 20}{Sin\: 20} + \frac{Sin\: 31}{Sin\: 31}- 8(\frac{1}{4})

= 1 + 1 - 2

= 0
Answered by sai7932
1
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