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let A and B be two sets having p and q elements respectively such that q-p<0 . if maximum value of (A union B) and (A intersection B) are m and m respectively. then (m+n) =
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Given A and B are two sets with number of elements p and q respectively.
The cartesian product of A and B=A×B={(a,b):(a∈A) and (b∈B)}
Number of elements in A×B=∣A×B∣=∣A∣.∣B∣=pq
Any relation from A to B is a subset of A×B.
Hence number of relations from A to B is the number of subsets of A×B
=2
∣A×B∣
=2
pq
Step-by-step explanation:
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