Question

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Answer 1

Answer:

Step-by-step explanation:

Let r be radius of inner circle and R be the radius of outer circle.

Given, d=4 cm and D=8 cm

Diameter of cone =8 cm ⇒x=  4cm

$\frac{4}{3 } \pi (R^{3}-r^{3} )$=$\frac{1}{3}\pi x^{2}h$

r=$\frac{4}{2}$=2cm ,   R=$\frac{8}{2}$=4cm

x=$\frac{8}{2}$=4cm ,  h=?

⇒$4(4^{3}-2^{3} )=4^{2}*h$

⇒4 ( 64 - 8 ) = 16 * h

⇒$h=\frac{56*4}{16}$

⇒h=14

Therefore, height of cone is 14 cm.