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Given: AB=8cm, AC=6cm, BC=10cm
to find: AD and area of triangle ABC
BC=BD+DC
BD+DC=10
BD=10-DC
here angle ADB is 90°
by Pythagoras theorem
AB^2=AD^2+BD^2
to find: AD and area of triangle ABC
BC=BD+DC
BD+DC=10
BD=10-DC
here angle ADB is 90°
by Pythagoras theorem
AB^2=AD^2+BD^2
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