Question

answers the above question by factorisation​

Answer 1

Answer:

here is the required answer

Explanation:

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Answer 2

Answer:

(3x-√6)(x-√2/3) or (√3x-√2)(√3x-√2)

is the factorisation

Explanation:

• we have the expression:
• 3x²-2√6 x + 2 = 0
• by middle term splitting method,
• find the two terms which are added to give -2√6x and multiply to give 6x².
• we find the two terms are -6x and -6x,
• $3x^{2} -\sqrt{6}x -\sqrt{6}x+2=0$
• $=> 3x(x-\sqrt{\frac{2}{3} } )-\sqrt{6} (x-\sqrt{\frac{2}{3} })$
• $=> (3x-\sqrt{6} )(x-\sqrt{\frac{2}{3} } )$ (Ans.)

• or we can find it by squaring method,

• (√3 x)²-2×√3x ×√2+(√2)²=0
• (√3x-√2)²=0
• (√3x-√2)(√3x-√2)=0(Ans.)

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