Question

ANSWERS THE GIVEN QUESTIONS NUMBER 1 and 2 and 3 .

THANKS

Answer 1

1).CSA of cylinder=88
2πrh=88
2×22/7×r×14=88
88r=88
r=88/88=1cm
2)sheet required=TSA of cylinder
=2πr(h+r)
=2×22/7×70(100+70)
=440(170)=74800cm³
3) continuation......
TSA=ISa+OSa+area of 2bases
=968+1064.8+5.28=2038.08 cm².
HOPE IT WAS HELPFUL

Answer 2

1.
Let r be the radius of the base and h = 14 cm be the height of the cylinder.
Curved surface area of cylinder = 2πrh = 88 cm2
⇒ 2 × 22/7 × r × 14 = 88
⇒ r = 88/ (2 × 22/7 × 14)
⇒ r = 1 cm
Thus, the diameter of the base = 2r = 2×1 = 2cm
2.____________
Let r be the radius of the base and h be the height of the cylinder.
Base diameter = 140 cm and Height (h) = 1m
Radius of base (r) = 140/2 = 70 cm = 0.7 m
Metal sheet required to make a closed cylindrical tank = 2πr(h + r)
= (2 × 22/7 × 0.7) (1 + 0.7) m2
= (2 × 22 × 0.1 × 1.7) m^2
=7.48 m2
3._______________
Let R be external radius and r be the internal radius h be the length of the pipe.
R = 4.4/2 cm = 2.2 cm
r = 4/2 cm = 2 cm
h = 77 cm
(i) Inner curved surface = 2πrh cm2
= 2 × 22/7 × 2 × 77cm2
= 968 cm2
(ii) Outer curved surface = 2πRh cm2
= 2 × 22/7 × 2.2 × 77 cm2
= 1064.8 cm2
(iii) Total surface area of a pipe = Inner curved surface area + outer curved surface area + areas of two bases
= 2πrh + 2πRh + 2π(R2 - r2)
= [968 + 1064.8 + (2 × 22/7) (4.84 - 4)] cm2
= (2032.8 + 44/7 × 0.84) cm2
= (2032.8 + 5.28) cm2 = 2038.08 cm2