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Express x = - y/2 - 5 in the form ax + by + c = 0 and write the values of a , b and c
Sol : x = - y/2 - 5
= x + y/2 + 5 = 0
= 1(x) + (1/2)(y) + 5 = 0
So , ax + by + c = 0
Wherein a = 1 , b = 1/2 , c = 5.
A driver hires an auto rickshaw the fair is rupees 20 for the first kilometre and rupees 9 for the subsequent distance taking total distance covered as X kilometre and the total fare as rupees y form a linear equation .
Sol : Fair for first kilometre = rupees 20
Fair for subsequent distance = rupees 9
Total distance given = x km
Total fair = rupees y
Rupees y = 1 × 20 + (x - 1) 9
So the required equation is y = 9 (x - 1) + 20
Let x be 1 , Then
y = 9 × 0 + 20
y = 20
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