answre the 2nd question
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Given that, a = 9, d = 8 and Sn = 636
Now
We know:

636 
636=  (18 + 8N -8)
636 = N(9 +4N -4)
4N2 +5N -636 =0
2N2 -N -45 =0
(4N +53)(N – 12)
Now, n = - 53/4 and n = 12
Taking the integral value and rejecting the fractional value, we have n = 12
Now
We know:

636 
636=  (18 + 8N -8)
636 = N(9 +4N -4)
4N2 +5N -636 =0
2N2 -N -45 =0
(4N +53)(N – 12)
Now, n = - 53/4 and n = 12
Taking the integral value and rejecting the fractional value, we have n = 12
Answered by
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go on https://www.algebra.com/algebra/homework/Sequences-and-series
:)
that will help you
happy to help
:)
that will help you
happy to help
ashanbhangu:
thanx
ur welcome :)
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