Question

to divide a line segment AB in the ratio 5 : 7 first AC is drawn so that angle BAX is acute angle and then at equal distance points are marked on the ray AX. find the minimum number of these points

Answer 1

to divide a line segment AB in the ratio ,m : n, a ray AX making an acute ∠BAX, is drawn and then m + n points are marked at equal distances on the ray AX.

Here, m = 5, n = 7

Therefore, minimum number of points to be marked on AX = m + n = 5 + 7 = l2.

Answer 2

12 points are required  To divide a line segment AB in the ratio 5:7

Step-by-step explanation:

To divide a line segment AB in the ratio 5:7,

Step1 : Draw a line segment AB  of some length

Step 2 :  Draw a line segment AX such that ∠BAX is an acute angle

Step 3:  Take 12 point on AX of Equal length one by one ( consecutively)

Step 4 :  Join 12th Point with B as a straight line

Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 5th point of step 3 and intersect AB at M

M divides AB in to  5  : 7 Ratio.

12 points are required

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