Question

Seven times a two digit number is equal to four times the number obtained by reversing the digits. If the difference between the digits is 3, find the number.

Answer 1

x =0 ,y =0 ,10x+y= 0

Answer 2

Let the one’s digit be ‘a’ and ten’s digit be ‘b’.
Given, seven times a two-digit number is equal to four times the number obtained by reversing the digits.
⇒ 7(10b + a) = 4(10a + b)
⇒ 66b = 33a
⇒ a = 2b ----- (1)
Also, difference between the digits is 3
⇒ a – b = 3
⇒ 2b – b = 3
Thus, b = 3
⇒ a = 2 × 3 = 6
Number is 36.