Question

answwr this question​

Answer 1

Dear Student,

4y2−12y+9

=(2y)2−2(2y)(3)+(3)2

=(2y−3)2

[Using identity: a2−2ab+b2=(a−b)2] =(2y−3)(2y−3)⇒4y2−12y+9=(2y−3)(2y−3)