Question

Anti derivative of sin 2x FASTT Please

Answer 1

Answer:

$\sf{}\because sin2x=\dfrac{d}{dx}\bigg\lgroup-\dfrac{1}{2} cos2x\bigg\rgroup$

Step-by-step explanation:

The anti derivative of sin 2x is a function of x whose derivative is sin 2x.

It is known that,

$\sf{}\dfrac{d}{dx}(cos2x)=-2sin 2x$

$\sf{}\Rightarrow sin2x=-\dfrac{1}{2}.\dfrac{d}{dx}(cos2x)$

$\sf{}\because sin2x=\dfrac{d}{dx}\bigg\lgroup-\dfrac{1}{2} cos2x\bigg\rgroup$

$\sf{Therefore,\ the\ anti\ derivative\ of\ sin 2}\ is\ -\dfrac{1}{2}cos2x$