.In the given figure, find PM (a) 3 cm (b) 5 cm (c) 4 cm (d) 2 cm
Answers
Answer:
In the given figure ∠LOP = ∠MOP , OL = 3cm , OP = 5cm , ∠PLO = ∠PMO [ as right angles ]
Firstly we have to prove that traingle LOP is congruent to traingle mop
se we will proof the congruence of those traingle
s
In traingle LOP and traingle MOP
∠LOP = ∠MOP
OP = OP [common]
∠PLO = ∠PMO [ right angles ]
Hence , ΔLOP ≅ΔMOP
PM = PL [ by CPCT ]
So , here we have got to know that PL = PM so if we find tHe value of PL it will be equal to PM
So , we can find the value of PL by the pythagoras theorem that is to be applied in ΔPLO ,
OP²= LP²+OL²
[5]²= [3]²+LP²
25= 9 +LP²
LP²= 25- 9
LP= √16 = 4cm
As we know that PM= PL
So , PL = PM = 4cm
OPTION [C]
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Answer:
In triangle LOP and triangle MOP
Angle LOP=angle MOP
OP= OP (common)
angle PLO=angle PMO(right angle)
By,pyathagoreas theorem
OP²=LP²+OL²
(5)²=(3)²+LP²
25=9+LP²
25-9=LP²
√16=LP
4cm=LP
So,PL=PM=4cm
I hope it is helpful for you