Physics, asked by BrainlyHelper, 1 year ago

Anton dropped a ball from the top of the building as high as 76.65m. At the same time, Rahmad walked near the building with a constant speed of 1.8 m / s. If the ball is right about the head of the rahmad, then the distance from the foot of the building is rahmad?


Give<span class="_wysihtml5-temp-placeholder"></span>n: g = 10 m / s
H = 76.65 - 1.65 = 75 m
V of rahmad = 1.8 m / s

Answers

Answered by duragpalsingh
0
A = Anton
Rahmad
Fall time Anton

h = ¹ / ₂ g t²
75 = ¹ / ₂ · 10 · t²
15 = t² t = √15 s
Rahmad distance
S = v t = 1.8 √15 m
Answered by kokan6515
0
Here is the answer in pic..
Attachments:
Similar questions