Question

Anu is 4 years older than Sunil 8 years ago Anu was three times Sunil age find the ages of Sunil and Anu

Answer 1

Age of Sunil = k

Age of Anu   = k+4

After 8 years

(k+4) - 8 = 3(k-8)

⇒ k - 4   = 3k - 24

⇒ k - 3k = -24 + 4

⇒ -2k     = -20

⇒ k         = -20/-2

               = 10

Age of Sunil = k

                      = 10

Age of Anu   = k+4

                      = 10+4

                      = 14
∴ Age of Sunil is 10 and age of Anu is 14

Answer 2

${\red{\underline{\underline{\large{\mathtt{Question:-}}}}}}$

Anu is 4 years older than Sunil 8 years ago Anu was three times Sunil age find the ages of Sunil and Anu.

${\red{\underline{\underline{\large{\mathtt{To\: find:-}}}}}}$

Age of Sunil and Anu.

${\red{\underline{\underline{\large{\mathtt{Answer:-}}}}}}$

Let the age of Sunil be $\bold{x}$

Anu's age= $\mathrm{x+4}$

8 years ago, Anu was 3 times Sunil's age.

$\underline\green{\star{\:\textsf{Equation:-}}}$

$\implies{(x + 4)} - 8 = 3(x - 8) \\ \implies \: x - 4 = 3x - 24 \\ \implies \: x - 3 = - 24 + 4 \\ \implies \: - 2x = - 24 \\ \implies \: x = \cancel\frac{ - 20}{-2} \\ \bold{x = 10}$

Hence,

$\bold\red{Age\:of\:Sunil=10\:years}$

$\bold\purple{Age\:of\:Anu=(10+4)years=14years}$

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