If E,F,G,and H are respectively the mid-points of the sides of a parallelogram ABCD, show that
ar(EFGH)=1/2 ar(ABCD)..
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contruct HF// AB//CD
NOW ,
ar. tri. NEM = 1/2 ar. //gm ABFH. ................. ( triangle inside a //gm ABFH & on same base MN)----------------(1)
Similarly,
ar. tri. HGF = 1/2 ar. tri. //gm HFDC. ----------------(2)
SO, BY ADDING (1) & (2),
ar EFGH = 1/2 ar .ABCD.
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NOW ,
ar. tri. NEM = 1/2 ar. //gm ABFH. ................. ( triangle inside a //gm ABFH & on same base MN)----------------(1)
Similarly,
ar. tri. HGF = 1/2 ar. tri. //gm HFDC. ----------------(2)
SO, BY ADDING (1) & (2),
ar EFGH = 1/2 ar .ABCD.
HOPE IT WILL HELP YOU. . . . . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! ! ! ! ! ! ! ! ! !
Plz mark my answer as brainliest
My camera was not working so I gave u only the solution.
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see I hv editted it
diagram is same as the above answer
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