Question

Anu is four years older than Sunil 8 years ago Anu was three times Sunil age find the ages of Anu and Sunil​

Answer 1

Answer:

Anu is presently 14 years old and Sunil is 10 years old.

Step-by-step explanation:

Given :

Anu is = 4 years older than Sunil

8 years ago = Anu was thrice the age of Sunil

To find :

Their present ages

Solution :

Let the present ages be -

• Sunil as y
• Anu as y + 4

$\rule{300}{1.5}$

Ages 8 years ago -

• Sunil = (y - 8)
• Anu = (y + 4) - 8

$\rule{300}{1.5}$

According to the Question -

8 years ago, Anu was three times age of Sunil.

⇒ (y + 4) - 8 = 3(y - 8)

⇒ y - 4 = 3y - 24

⇒ - 4 + 24 = 3y - y

⇒ 20 = 2y

⇒ y = 20/2

⇒ y = 10

Sunil's present age = 10 years

$\rule{300}{1.5}$

★ Value of (y + 4)

⇒ 10 + 4

⇒ 14

Anu's present age = 14 years

$\therefore$ Anu is presently 14 years old and Sunil is 10 years old.

Answer 2

Answer:

$\bold\red{Sunil's\:present\:age = 10 years}$

$\bold\red{Anu's\:present\:age = 14 years}$

Step-by-step explanation:

Let the present age of Sunil be 'x' years.

Now ,

it is being given that,

Anu is four years older than Sunil,

Therefore,

Present age of Anu will be (x+4) years.

Also,

8 years ago from now,

Age of Sunil = (x -8) years

Age of Anu = {(x+4)-8} = (x - 4) years

But,

It is given that,

Anu was three times Sunil's age

Therefore,

we get,

=> x - 4 = 3( x - 8)

=> x - 4 = 3x - 24

=> 3x - x = 24 - 4

=> 2x = 20

=> x = 10

Therefore,

x + 4 = 10 + 4 = 14

Hence,

Sunil's present age = 10 years

Anu's present age = 14 years