Anu is four years older then Sunil . Eight years ago Anu was three times Sunil’s age . Find the ages of any and Sunil
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let , anu = x , sunil = y
given , anu is four year old then sunil
so, x = y+4
eight year ago
==> (x-8) = 3(y-8)
==> x -8 = 3y-24
==> x-3y = -24+8
==> x-3y = -16 ..(1)
now putting the value of x in eq(1)
==> x - 3y = -16
==> (4+y)-3y = -16
==> 4 -2y = -16
==> -2y = -20
==> y = 10
so, x = 10+4 ==> 14
so, anu age = 14 , and sunil = 10
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