Question

anwer my question guys​

Answer 1

Explanation:

To Find -

• Oxidation number of the following underlined atom

Solution -

1)

K2Cr2O7

Let x be the O.N. of Cr

Then,

→ 1×2 + 2x - 2×7 = 0

→ 2x = 12

→ x = +6

2)

HNO3

Let x be the O.N. of N

Then,

→ 1 + x - 2×3 = 0

→ x = +5

3)

H2SO4

Let x be the O.N. of S

Then,

→ 1×2 + x - 2×4 = 0

→ x = +6

4)

SO4²-

Let x be the O.N. of S

Then,

→ x - 2×4 = -2

→ x = -2 + 8

→ x = +6

5)

Cr2O7²-

Let x be the O.N. of Cr

Then,

→ 2x - 2×7 = -2

→ 2x = 14 - 2

→ 2x = 12

→ x = +6

6)

MgSO4

Let x be the O.N. of S

Then,

→ 2 + x - 2×4 = 0

→ x = +6

Answer 2

Answer:

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