Any 1 who could help me with the question !!!.....
given that HCF(2520 ,6600)=40 and LCM(2520 ,6600)=252 × k,then find the value of k.
Answers
Answered by
12
Hey mate !!
Here's your answer !!
Given :
HCF ( 2520, 6600 ) = 40
LCM ( 2520, 6600 ) = 252 * K
To Find :
K = ?
Proof :
We know that, LCM * HCF = Product of two numbers
=> ( 252 * k ) * ( 40 ) = 2520 * 6600
=> 10080 * k = 16632000
=> K = 16632000 / 10080
=> K = 1650
Hence value of K is 1650.
Hope my answer helped !!
Cheers !!
Here's your answer !!
Given :
HCF ( 2520, 6600 ) = 40
LCM ( 2520, 6600 ) = 252 * K
To Find :
K = ?
Proof :
We know that, LCM * HCF = Product of two numbers
=> ( 252 * k ) * ( 40 ) = 2520 * 6600
=> 10080 * k = 16632000
=> K = 16632000 / 10080
=> K = 1650
Hence value of K is 1650.
Hope my answer helped !!
Cheers !!
shuzu:
tq buddy...^-^
Answered by
3
Hi ,
****************************
We know that ,
If a, b are two positive Integers and
their HCF = H , LCM = L then
a × b = L × H
********************************
Now ,
a = 2520 ,
b = 6600 ,
H = 40 ,
L = 252 × k
L × H = a × b
252 × k × 40 = 2520 × 6600
k = ( 2520 × 6600 )/( 252 × 40 )
= 1650
Therefore ,
k = 1650
I hope this helps you.
: )
****************************
We know that ,
If a, b are two positive Integers and
their HCF = H , LCM = L then
a × b = L × H
********************************
Now ,
a = 2520 ,
b = 6600 ,
H = 40 ,
L = 252 × k
L × H = a × b
252 × k × 40 = 2520 × 6600
k = ( 2520 × 6600 )/( 252 × 40 )
= 1650
Therefore ,
k = 1650
I hope this helps you.
: )
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