Question

any 4 consecutive numbers whose sum is 45

Answer 1

Answer:

$Required \: four \: consecutive \: numbers\\are , 9.5, 10.5 , 11.5 \: and \: 12.5$

Step-by-step explanation:

$Let \: x,x+1,x+2 \: and \: x+3 \: are \: four\\ consecutive\: numbers$

$Sum \: four \: numbers = 45 \:(given)$

$\implies x + x+1 + x+2 + x+3 = 45$

$\implies 4x + 7 = 45$

$\implies 4x = 45 - 7$

$\implies 4x = 38$

$\implies x = \frac{38}{4}$

$\implies x = 9.5$

$Now, Required \: four \: consecutive \\ numbers \:are ,\\</p><p>x = 9.5,\\x+1 = 9.5 + 1 = 10.5 \\x+2= 9.5+2 = 11.5\\x+3 = 9.5+3 = 12.5$

Therefore.,

$Required \: four \: consecutive \: numbers\\are , 9.5, 10.5 , 11.5 \: and \: 12.5$

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