any body able to solve the number 10 and 11 (rounded one) shown above.
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hello,
(100*5 + 100*3 + 100*x + 100*2 + 100*1)/6 = 350
(500 + 300 + 300 + 100x + 200 + 100)/6 = 350
(800+500+100+100x)/6=350
(1400 + 100x)/6 =350
(100x)/6 = 1050
x = (1050*6)/100
x = (1050*6)/100
x = 6300/100
x= 63
11)
greater than 250 = 0
greater than 200 = 15
greater than 150 = 30-15=15
greater than 100= 30
greater than 50 = 20
greater than 0 = 10
ascending order is
0,10,15,15,20,30
n=6
median = 15+15/2
median = 15
(100*5 + 100*3 + 100*x + 100*2 + 100*1)/6 = 350
(500 + 300 + 300 + 100x + 200 + 100)/6 = 350
(800+500+100+100x)/6=350
(1400 + 100x)/6 =350
(100x)/6 = 1050
x = (1050*6)/100
x = (1050*6)/100
x = 6300/100
x= 63
11)
greater than 250 = 0
greater than 200 = 15
greater than 150 = 30-15=15
greater than 100= 30
greater than 50 = 20
greater than 0 = 10
ascending order is
0,10,15,15,20,30
n=6
median = 15+15/2
median = 15
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