Math, asked by sanyam80, 1 year ago

any body able to solve the number 10 and 11 (rounded one) shown above.​

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Answers

Answered by jugal07
0
hello,

(100*5 + 100*3 + 100*x + 100*2 + 100*1)/6 = 350

(500 + 300 + 300 + 100x + 200 + 100)/6 = 350

(800+500+100+100x)/6=350

(1400 + 100x)/6 =350

(100x)/6 = 1050

x = (1050*6)/100

x = (1050*6)/100

x = 6300/100

x= 63


11)

greater than 250 = 0

greater than 200 = 15

greater than 150 = 30-15=15

greater than 100= 30

greater than 50 = 20

greater than 0 = 10

ascending order is

0,10,15,15,20,30

n=6

median = 15+15/2

median = 15
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