Question

Any body help me plzz

Answer 1

given. AB=AC and BD=CE. To prove BE=CD
now if AB=AC then angle ABC= ANGLE ACB as angles opp to equal sides are equal
now
in ∆BDC and in ∆CEB
BD=CE. given
BC=BC. common
now we know that ABC=ACB. subtracting 180°from both the sides
180-ABC=180-ACB
CBD=BCE

SO bySAS rule
∆BDC is congruent to ∆CEB
So by CPCT, BE=DC
Hence proven

Answer 2

in triangle DBC and ECB
BD= CE
angle DBC= angle BCE
adage BC is comman
so that triangle DBC and Triangle BCE is a SAMROOP so that DC=BE