any bold help in proof this question
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Let BP=x
PQ = x
QC = x
Area of parallelogram = base × height
= 3x × h
Area of APQ = 1/2 × x × h
Area of DPQ = 1/2 × x × h
Equating all three, we will get the same given equation.
PQ = x
QC = x
Area of parallelogram = base × height
= 3x × h
Area of APQ = 1/2 × x × h
Area of DPQ = 1/2 × x × h
Equating all three, we will get the same given equation.
VarunGupta11:
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