Question

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Answer 1

Ans. Width of the canal= 30 dm=300 cm

Depth of the canal = 12 dm=120 cm

Velocity of the flow of the water in canal = 20km/hr= 20 × 1000 × 100 cm/hr

Volume of water flowed in 1 hour = 300 × 120 × 2000000 cm3

Volume of water flowed in 30 min (1/2hour) = 300 × 120 × 2000000 x 1/2 =

300 × 120 × 1000000 cm3 (1)

Let area irrigated is A and height of standing water is 9 cm.

So volume required = A × 9 cm3 (2)

From (1) and (2)

A x 9 = 300 × 120 × 1000000

=> A = 4000000000 cm2 = 400000 m2 = 0.4 km2

therefore the area irrigated by this water if 9 cm of standing water is desired, 0.4 km2

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