any maths expert here pls solve this pls pls pls
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Given
ABCD is a Rectangle
Therefore,
Angle XYX = 90⁰
Angle YZW = 90⁰
Angle ZWX = 90⁰
Angle WXY = 90⁰
WX = ZY
WZ = XY
To Find
Angle b and Angle a
Answer
Angle XYZ = 90⁰
Angle XYZ = Angle WYX + Angle WYZ
90⁰ = 59⁰ + a
90⁰ - 59⁰ = a
31⁰ = a
or
a = 31⁰
Angle a = Angle WXZ
Angle WXZ = 31⁰
Angle WXY = 90⁰
Angle WXY = Angle WXY + Angle ZXY
90⁰ = 31⁰ + Angle ZXY
90⁰ - 31⁰ = Angle ZXY
59⁰ = Angle ZXY
Angle WUZ = Angle XUY
b = Angle XUY
Angle ZXY + Angle WYX + Angle XUY = 180⁰
59⁰ + 31⁰ + b =180⁰
b = 180⁰ - 90⁰
b = 90⁰
Hope it helps you, hv a nyc day
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