Math, asked by nikhilvishwakarma59, 1 year ago

sec⁴A-tan⁴A=1+tan²A​

Answers

Answered by Anonymous
2

Answer:

LHS =sec^4A - sec^2A

=sec^2A (sec^2A-1)

=sec^2A .tan^2A {because sec^2A-tan^2A=1 }

=(1+tan^2A) tan^2A

=tan^4A+tan^2A =RHS

Thanks for the question dear.

Hope it helps you.

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