Math, asked by Atlas99, 17 days ago

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Answers

Answered by amitkumar44481
110

Answer :

{ 1 , 2 , 3 , 4 , 5 }

To Find :

The solution of given inequality on the number line.

SolutioN :

\tt \rightarrow \:  -   \frac{2}{3}   \leq \dfrac{x}{3}  \leq  \dfrac{2}{3}  ,  \: where \:  x \: ∈  \:  R.\\  \\

Taking Inequality 1.

\tt \rightarrow \:   -    \frac{2}{3} \leq \dfrac{x}{3}  - 1 .  \\  \\

\tt \rightarrow \:   1-    \frac{2}{3} \leq \dfrac{x}{3}   .  \\  \\

\tt \rightarrow \:   1 \leq x.  \: \:  \:    - (1)\\  \\

Taking Inequality 2.

\tt \rightarrow \:      \frac{x}{3} - 1 \leq \dfrac{2}{3}   .  \\  \\

\tt \rightarrow \:      \frac{x}{3}  \leq \dfrac{5}{3}   .  \\  \\

\tt \rightarrow \:      x \leq 5.  \: \:  \: -(2)    \\  \\

From equation 1 and 2, we get.

•°• Solution of set is { 1 , 2 , 3 , 4 , 5 }

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MasterDhruva: Nice!
anindyaadhikari13: Perfect!
amitkumar44481: Thank you both :-)
Answered by tennetiraj86
78

Step-by-step explanation:

Given :-

-2/3 ≤ (x/3)-1 ≤ 2/3 where x € R

To find :-

Solve the in-equation and graph the solution on the number line?

Solution :-

Given in-equation is -2/3 ≤ (x/3)-1 ≤ 2/3

On adding 1 both sides

=> (-2/3)+1 ≤ (x/3)-1+1 ≤ (2/3)+1

=> (-2+3)/3 ≤ (x/3)+0 ≤ (2+3)/3

=>(-2+3)/3 ≤ (x/3) ≤ (2+3)/3

=> 1/3 ≤ x/3 ≤ 5/3

On multiplying with 3 both sides then

=> 3(1/3) ≤ (x/3)×3 ≤ 3(5/3)

=> 3/3 ≤ 3x/3 ≤15/3

=> 1 ≤ x ≤5

The value of x lies between 1 ,2 , 3, 4, 5 (including 1 and 5)

Answer:-

The solution set for the in-equation is { 1,2,3,4,5}

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amitkumar44481: Great :-)
anindyaadhikari13: Superb!
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