Any one answer this
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i think here x is distance
v = distance / time
distance = 1250 × 10^2 × 10^-2 × 10^-3
= 1250 × 10^-3 km
time = 1 hr
v = 1250×10^-3 / 1
= 125×10^-2 km/hr
v = distance / time
distance = 1250 × 10^2 × 10^-2 × 10^-3
= 1250 × 10^-3 km
time = 1 hr
v = 1250×10^-3 / 1
= 125×10^-2 km/hr
vishalsaini:
if motion in straight line then distance and displacement both are same
is it right?
Bro it's right but answer should be converted to meters because the unit of vilocity is m/sec
bro both are correct
OK Bro thanks for your answer a got an idea how to solve by seeing your answer
your welcome
you can convert it in m/sec by multiplying 5÷18
5/18
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