Question

any one can tell me and of these questions
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Answer 1

Answer:

hmm easy take it easy is question ko chodd do

Answer 2

Answer:

Let the cost price of one watch be x

therefore,

cost price of another watch is (840-x)

Selling price of first watch is 116x/100

selling price of second watch is 88(840-x)/100

A/Q,

116x/100+88(840-x)/100 = 840

116x+88(840-x) = 840 *100

116x+73920-88x = 84000

28x = 84000 - 73920

28x = 10080

x = 10080/28

x=360

cost price of first watch is x = 360

cost price of second watch is (840-x) = 840-360

= 480

Step-by-step explanation:

Hope it helps yrr