any one can tell me and of these questions
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hmm easy take it easy is question ko chodd do
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Let the cost price of one watch be x
therefore,
cost price of another watch is (840-x)
Selling price of first watch is 116x/100
selling price of second watch is 88(840-x)/100
A/Q,
116x/100+88(840-x)/100 = 840
116x+88(840-x) = 840 *100
116x+73920-88x = 84000
28x = 84000 - 73920
28x = 10080
x = 10080/28
x=360
cost price of first watch is x = 360
cost price of second watch is (840-x) = 840-360
= 480
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Hope it helps yrr
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