any one is here to solve my question
I think no one is there to solve this.
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Answer:
r cosec(α/2) sinβ
Step-by-step explanation:
Let the observer is at A.
Let NA,MA are tangents from A to the balloon.
∴ ∠MAN = α.
∠MAD = ∠NAO = α/2
Given that,
∠PAO = β
∴ OM/OA = sin α/2
OA = r cosec(α/2) ---- (i)
∴ OP/OA = sin β
OP = OA sin β
= r cosec(α/2) sin β.
Hope it helps!
r cosec(α/2) sinβ
Step-by-step explanation:
Let the observer is at A.
Let NA,MA are tangents from A to the balloon.
∴ ∠MAN = α.
∠MAD = ∠NAO = α/2
Given that,
∠PAO = β
∴ OM/OA = sin α/2
OA = r cosec(α/2) ---- (i)
∴ OP/OA = sin β
OP = OA sin β
= r cosec(α/2) sin β.
Hope it helps!
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siddhartharao77:
I think you wanna say something..Please tell..I dont mind!
no buddy
in which class do u study
i am not student.. brainly TEACHER!
oh iam sorry
sir
its ok..Come to inbox for any doubts..
ok sir
good ngt
hello sir please solve my question
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