Question

any solved question related to this equation

Answer 1

Hey.

Given : A ball is dropped from a tower under the influence of the gravity. It reaches the ground after 4 seconds. Find the height of the tower from where it was dropped .

Solution :

As the ball is dropped freely under gravity

so, initial velocity, u = 0 m/s, a= g = 10 m/s^2

time , t = 4 s

For calculating height of tower :

As,
$s \: = ut \: + \frac{1}{2} a {t}^{2} \\ \\ so \: \: s \: = 0 + \frac{1}{2} \times 10 \times {4}^{2} \\ \\ so \: \: s \: = 5 \times 16 = 80 \: m$

Hence, height of the tower will be 80 m.

Thanks.