Question

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Triangle ABC and BAD are drawn on the same side of the line segment AB such that AD = BC and ∠DAB =∠CBA. Then ​

Answer 1

Answer:

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Explanation:

Here, AB,BD,AD are sides of a triangle. These sides are given equal. Hence the triangle is an equilateral triangle.

Thus, ∠ADB=60∘

In △ADC,

AD=CD

Thus, ∠ADC=∠ACD=y (Isosceles triangle property)

Now, ∠ADB=∠ADC+∠ACD

60=y+y

y=30∘

∠ACD=30∘

∠ADC+∠ADB=180 (Angles on a straight line)

60+∠ADC=180

∠ADC=120∘

Hence, ∠C∠ADC=30120

∠C∠ADC=4:1