Question

any value of x for which the polynomial f(x) vanishes is called​

Answer 1

Answer:

ANSWER

f(x)=(x−1)(x+2)(ax+b)

f(−1)=4=(−2)(1)(b−a)

=a−b=2

f(2)=28=(1)(4)(2a+b)

2a+b=1

solving 1 and 2 equations

3a=9

a=3

b=1

∴f(x)=(x−1)(x+2)(3x+1)

f(0)=(−1)(2)(1)

=−2