anybody 8th grader here!!!!!
pls help me with this......
the base of an isosclecs triangle is 4/3 cm. the perimeter of a triangle is 4 2/5 cm. what is the length of either of the remaining equal sides.
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Ans= 23/15 cm
perimeter of triangle = side 1+side2+side3
let side1 and side2 be x
so,
x+x+4/3= 22/5
2x= 22/5-4/3
2x= (66-20)/15
2x=46/15
x= 23/15
perimeter of triangle = side 1+side2+side3
let side1 and side2 be x
so,
x+x+4/3= 22/5
2x= 22/5-4/3
2x= (66-20)/15
2x=46/15
x= 23/15
Answered by
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let the equal sides of the ∆ABC be 'a' and the base as 'b' by solving it you get the answer as 23/15cm hope u find this helpful
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